Re: Re: Re: Re: task 4

From Abrupt Leech, 2 Months ago, written in Plain Text, viewed 126 times. This paste is a reply to Re: Re: Re: task 4 from Emerald Owl - view diff

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SELECT ar.name,
       COUNT(al.album_id) AS alb_count
FROM artist AS ar
LEFT OUTER JOIN album AS al ON al.artist_id = ar.artist_id
GROUP BY ar.name
HAVING COUNT(al.album_id) is Null

Replies to Re: Re: Re: Re: task 4

Title	Name	Language	When
Re: Re: Re: Re: Re: task 4	Edgy Goose	text	2 Months ago.

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