From Commodious Agouti, 4 Months ago, written in Plain Text, viewed 65 times.
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  1. orders_a = orders.query('group == "A"')
  2. orders_b = orders.query('group == "B"')
  3. orders_b['visitor_id'].isin(orders_a['visitor_id']).loc[lambda x : x == True].count()

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Re: Untitled Crippled Cat text 4 Months ago.

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