- orders_a = orders.query('group == "A"')
- orders_b = orders.query('group == "B"')
- orders_b['visitor_id'].isin(orders_a['visitor_id']).loc[lambda x : x == True].count()
Re: Untitled
From Crippled Cat, 4 Months ago, written in Plain Text, viewed 62 times.
This paste is a reply to Untitled from Commodious Agouti
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URL http://codebin.org/view/b3ab4068
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